If rope of lift breaks suddenly, the tension exerted by the surface of lift

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Q: If rope of lift breaks suddenly, the tension exerted by the surface of lift (a = acceleration of lift)

(a) mg

(b) m (g + a)

(c) m(g – a)

(d) 0

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Ans: (d)
Sol: m g – T = ma

here , a = g

T = mg – ma

T = mg – mg = 0

 

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