Q: If the uncertainty in the position of proton is 6 ×10^{8} m, then the minimum uncertainly in its speed is

Sol: $\large \Delta p = m \Delta v = \frac{h}{\Delta x} $

or , $\large \Delta v = \frac{h}{m \Delta x} $

$\large \Delta v = \frac{6.62 \times 10^{-34}}{1.67 \times 10^{-27} \times 6 \times 10^{-8}} $

= 1 m/s