Q: If the uncertainty in the position of proton is 6 ×108 m, then the minimum uncertainly in its speed is
Sol: $\large \Delta p = m \Delta v = \frac{h}{\Delta x} $
or , $\large \Delta v = \frac{h}{m \Delta x} $
$\large \Delta v = \frac{6.62 \times 10^{-34}}{1.67 \times 10^{-27} \times 6 \times 10^{-8}} $
= 1 m/s