Q: In a common base amplifier circuit , calculate the change in base current if that in emitter current is 2 mA and α = 0.98
(a) 0.04 mA
(b) 1.96 mA
(c) 2 mA
(d) 98 mA
Ans: (a)
Sol: $\large \alpha = \frac{I_c}{I_e} $
Since Ie = Ib + Ic
$\large \alpha = \frac{I_e – I_b}{I_e} $
$\large 0.98 = \frac{2 – I_b}{2} $
Ib = 0.04 mA