In a given process of an ideal gas, dW = 0 dQ < 0. Then for the gas

Q: In a given process of an ideal gas, dW = 0 dQ < 0. Then for the gas

(a)The temperature will decrease

(b)The volume will increase

(c)The pressure will remain constant

(d)The temperature will increase

Ans: (a)

Sol: From First Law of thermodynamics ;

dQ = dU + dW

if , dW = 0 ; dQ = dU

Since , dQ < 0

$\large U_{final} < U_{initial}$

Hence , temperature will decrease .