# In a tank, a 4 cm thick layer of water (μ =4/3)floats on a 6 cm thick layer of an organic liquid (μ =1.5) viewing at normal incidence, how far below…

Q: In a tank, a 4 cm thick layer of water (μ =4/3)floats on a 6 cm thick layer of an organic liquid (μ =1.5) viewing at normal incidence, how far below the water surface does the bottom of tank appear to be ?

Sol: $\large d_{AP} = \frac{h_1}{\mu_1} + \frac{h_2}{\mu_2}$

$\large d_{AP} = \frac{6}{1.5} + \frac{4}{4/3}$

= 7 cm