In a transistor, a change of 8.0 mA in the emitter current produces a change of 7.9 mA in the collector current. The base current changes by

Q: In a transistor, a change of 8.0 mA in the emitter current produces a change of 7.9 mA in the collector current. The base current changes by

(a) 1  μA

(b) 10 μA

(c) 100 μA

(d) 1000 μA

Solution : I_E = I_B + I_C

ΔI_E = ΔI_B + ΔI_C

8 = ΔI_B + 7.9

ΔI_B = 0.1 mA = 0.1 × 10^-3 A = 10^-4 A

= 100 × 10^-6 A = 100 μA

Correct option is (c)