Q: In the circuit shown in figure initially key K1 is closed and key K2 open. Then K1 is opened and K2 is closed (order is important). [Take Q1‘ and Q2‘ as charges on C1 and C2 and V1 and V2 as voltage respectively.]
Then,
(a) Charge on C1 gets redistributed such that V1 = V2
(b) Charge on C1 gets redistributed such that Q1‘ = Q2‘
(c) Charge on C1 gets redistributed such that C1 V1 + C2 V2 = C1 E
(d) Charge on C1 gets redistributed such that Q1‘ + Q2‘ = Q
Ans: (a) & (d)
Solution : When key K1 is closed and key K2 open capacitor C1 is charged by the battery . When K1 is opened and K2 is closed the charged stored by the capacitor C1 will be redistributed between C1 and C2 . As C1 and C2 are in parallel hence V1 = V2