# In the nuclear reaction 92U235 → 82Pb207 , the number of  α and β particles lost would be

Q: In the nuclear reaction 92U23582Pb207 , the number of  α and β particles lost would be

(A) 8 , 4

(B) 6 , 2

(C) 7 , 4

(D) 4 , 3

Solution: 92U23582Pb207 + x (2α4) + y (-1β0)

235 = 207 + 4x  ⇒ x = 7

92 = 82 + 2x – y or y = 4

Ans: (C)