In the nuclear reaction: X(n , α) 3_Li^7 then term X will be

Q: In the nuclear reaction: X(n , α) ₃ Li⁷ then term X will be

(a) ₅B¹⁰

(b) ₅B⁹

(c) ₅B¹¹

(d) ₂He⁴

Ans: (a)

Sol: _ZX^A + ₀n¹ → ₂He⁴ + ₃Li⁷

Equating Atomic no.

Z + 0 = 2 + 3 ⇒ Z = 5

Equating mass no.

A +1 = 4 + 7 ⇒ A = 10

X is ₅B¹⁰