Q: Let T > 0 be a fixed real number. Suppose f is a continuous function such that for all x ∈ R f(x+T)= f(x). If $I = \int_{0}^{T} f(x) dx $ , then the value of $ \int_{0}^{3+3T} f(2x) dx $ is
(A) $\frac{3}{2}I $
(B) 2I
(C) 3I
(D) 6I
Sol: Let $\large L = \int_{0}^{3 + 3T} f(2x) dx $
Put 2x = t so that
$\large L = \frac{1}{2}\int_{0}^{6 + 6T} f(t) dt $
$\large L = \frac{6}{2}\int_{0}^{T} f(t) dt = 3 I$
Hence (C) is the correct answer.
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