Light takes t1 sec to travel a distance x cm in vacuum and takes t2 sec to travel 10x cm in a medium. The critical angle…..

Q.Light takes t1 sec to travel a distance x cm in vacuum and takes t2 sec to travel 10x cm in a medium. The critical angle corresponding to the media is

(a)sin-1(10t1/t2)

(b) sin-1(t2/(10t1 ))

(c) sin-1(10t2/t1 )

(d) sin-1(t1/(10t2 ))

Ans:(a)

Sol: t1 = x/c , t2 = 10x/(c/μ ) = 10xμ/c

Hence , t2 = 10μt1 => μ= t2/10t1

sinθ = 1/μ =10t1/t2

θ = sin−1(10t1/t2)

Author: Rajesh Jha

QuantumStudy.com

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