$\lim_{x \rightarrow 1} \frac{sec^{-1}(2-x)}{x^2}$ is equal to by author Q: $\lim_{x \rightarrow 1} \frac{sec^{-1}(2-x)}{x^2}$ is equal to (A) 0 (B) 1/2 (C) 4 (D) does not exist Ans: (D) Also Read :$lim_{x rightarrow 0} (frac{a^x + b^x + c^x}{3})^{2/x}$ , a, b, c > 0 is equal toIntegrate : $ lim_{x rightarrow infty}…$ lim_{n rightarrow infty} (frac{1}{n} + frac{e^{1/n}}{n} + frac{e^{2/n}}{n} + ....+…lim_ n →∞ (n!/(mn)^n)^(1/n) (m ∈ N) is equal to If for non-zero x , $ 3 f(x) + 4 f(frac{1}{x}) = frac{1}{x} - 10 $ then $int_{2}^{3}f(x)…Let $S= Sigma_{i=1}^{n} a_i $ and Show that $ Sigma_{i=1}^{n} frac{s}{s-a_i} >…$ frac{1}{1!(n-1)!} - frac{1}{3!(n-3)!} + frac{1}{5!(n-5)!} - ...is ; equal ; to $Given $f(x) = lnfrac{1 + x}{1 - x}$ and $g(x) = frac{3x + x^3}{1 + 3x^2}$ . Then f(g(x))…$int ( x + frac{1}{x})^{n+5} (frac{x^2 -1}{x^2})dx $ is equal to$ int frac{(x + x^{2/3} + x^{1/6})}{x(1 + x^{1/3})} dx $ is equal to