__DEFINITION : CONIC SECTION__

A conic section or conic is the locus of a point, which moves in a plane so that its distance from a fixed point is in a constant ratio to its distance from a fixed straight line, not passing through the fixed point.

∎ The fixed point is called the focus.

∎ The fixed straight line is called the directrix.

∎ The constant ratio is called the eccentricity and is denoted by e.

∎ When the eccentricity is unity; i.e., e = 1 , the conic is called a parabola;

when e < 1, the conic is called an ellipse .

and when e > 1, the conic is called a hyperbola.

∎ The straight line passing through the focus and perpendicular to the directrix is called the axis of the parabola.

∎ A point of intersection of a conic with its axis is called vertex.

__Standard equation of a Parabola:__

Let S be the focus, ZM the directrix and P the moving point. Draw SZ perpendicular from S on the directrix. Then SZ is the axis of the parabola. Now the middle point of SZ , say A , will lie on the locus of P ,

i.e., AS = AZ

Take A as the origin, the x-axis along AS, and the y-axis along the perpendicular to AS at A, as in the figure.

Let AS = a , so that ZA is also a .

Let (x, y) be the coordinates of the moving point P.

Then MP = ZN = ZA + AN = a + x .

But by definition MP = PS

⇒ MP^{2} = PS^{2}

So that , (a + x)^{2} = (x – a)^{2} + y^{2}

Hence , the equation of parabola is y^{2} = 4ax

__Latus Rectum:__

The chord of a parabola through the focus and perpendicular to the axis is called the latus rectum.

In the figure LSL’ is the latus rectum.

Also LSL’ = 4a = double ordinate through the focus S.

Note:

∎ Any chord of the parabola y^{2} = 4ax perpendicular to the axis of the parabola is called double ordinate.

∎ Two parabolas are said to be equal when their latus recta are equal.

Four common forms of a Parabola

### Four common forms of a Parabola:

Form : y^{2} = 4ax

∎ Vertex : (0, 0)

∎ Focus : (a , 0)

∎ Equation of the Directrix: x = −a

Form: y^{2} = −4ax

∎ Vertex : (0 , 0)

∎ Focus : (-a , 0)

∎ Equation of the Directrix : x = a

Form : x^{2} = 4ay

∎ Vertex : (0 , 0)

∎ Focus : (0 , a)

∎ Equation of the Directrix : y = -a

Form: x^{2} = -4ay

∎ Vertex : (0 , 0)

∎ Focus : (0 , -a)

∎ Equation of the Directrix : y = a

Illustration : Find the vertex , axis , directrix, focus, latus rectum and the tangent at vertex for the parabola 9y^{2} − 16x − 12y − 57 = 0

Solution: The given equation can be rewritten as

$\large (x-\frac{2}{3})^2 = \frac{16}{9}(x+\frac{61}{16})$

which is of the form Y^{2} = 4AX.

Hence the vertex is (− 61/16 , 2/3)

The axis is y − 2/3 = 0

⇒ y = 2/3

The directrix is : X + A = 0

⇒ x + 61/16 + 4/9 = 0

⇒ x = − 613/144

The focus is X = A and Y = 0

⇒ x + 61/16 = 4/9 and y − 2/3 = 0

⇒ (− 485/144 , 2/3) is the focus

Length of the latus rectum = 4A = 16/9

The tangent at the vertex is X = 0

⇒ x = − 61/16

Illustration : The extreme points of the latus rectum of a parabola are (7, 5) and (7, 3). Find the equation of the parabola and the points where it meets the axes.

Solution: Focus of the parabola is the mid-point of the latus rectum.

⇒ S is (7, 4).

Also axis of the parabola is perpendicular to the latus rectum and passes through the focus. Its equation is

y − 4 = 0(x − 7)/(5−3)

⇒ y = 4

Length of the latus rectum = (5 − 3) = 2

Hence the vertex of the parabola is at a distance 2/4 = 0.5 from the focus. We have two parabolas, one concave rightwards and the other concave leftwards.

The vertex of the first parabola is (6.5, 4)

and its equation is (y − 4)^{2} = 2(x − 6.5)

and it meets the x-axis at (14.5 , 0).

The equation of the second parabola is

(y − 4)^{2} = −2(x − 7.5).

It meets the x-axis at (−0.5, 0) and the y-axis at (0, 4 ± √15).

Exercise :

(i) Find the equation of parabola whose focus is (1, −1) and whose vertex is (2, 1). Also find its axis and latus rectum.

(ii) Find vertex, focus, directix and latus rectum of the parabola y^{2} + 4x + 4y − 3 = 0.

(iii) Find the equation of the parabola whose axis is parallel to the y – axis and which passes through the points (0, 4), (1, 9) and (−2, 6) and determine its latus rectum.