NaIO3 reacts with NaHSO3 according to equation

Q: NaIO3 reacts with NaHSO3 according to equation

IO3 + 3HSO3  → I + 3H++ 3SO42–

The weight of NaHSO3 required to react with 100 ml of solution containing 0.58 gm of NaIO3 is

(A) 5.2 gm

(B) 4.57 gm

(C) 2.3 gm

(D) None of these

Sol: $\large \frac{W_{NaHSO_3}}{M_{NaHSO_3}} \times 2 \times 1000= \frac{0.58}{198}\times 6 \times 100 $

$\large W_{NaHSO_3} = 4.57 gm$

Ans: (B)