Q: One mole of an ideal gas undergoes a process $\displaystyle P = \frac{P_0 }{1 + (\frac{V_0}{V})^2}$ . Here , P_{0} and V_{0} are constants. Change in temperature of the gas when volume is change from V = V_{0} and 2 V_{0} is

(a) $\displaystyle \frac{2 P_0 V_0}{5 R}$

(b) $\displaystyle \frac{11 P_0 V_0}{10 R}$

(c) $\displaystyle \frac{5 P_0 V_0}{4 R}$

(d) P_{0} V_{0}

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Ans: (b)