**From Periodic Motion to SHM**

**Any motion that repeats itself after equal interval of time is called periodic motion.**

**If a particle, undergoing periodic motion, covers the same path back and forth about a mean position, it is said to be executing an oscillation (or vibration).**

**Using advanced mathematics, it can be shown that the displacement of a particle in an oscillation can always be expressed in terms of sines and cosines.**

**This, coupled with the fact that the term harmonic is generally applied to expressions containing sine and cosine functions actuates us to use the term harmonic motion for the oscillation.**

**Every harmonic motion is characterised by:**

** (i) time period**

** (ii) frequency**

**(iii) amplitude and**

**(iv) phase.**

**The Time Period (T) of a harmonic motion is the time required to complete one oscillation (or cycle).**

**The frequency (ν or n or f) of a harmonic motion is the number of oscillations per unit time.**

**From these definitions, it follows;**

**Our topic under discission is simple harmonic motion (SHM) and at this stage we just state it is a special type of harmonic motion.**

**Recalling Equilibrium :**

**Recalling Equilibrium :**

**Before investigating what exactly an SHM is, let us have a brief review of equilibrium of a particle (or body).**

**Without disturbing the continuity of discussion, it may be stated here that when a body is slightly disturbed from its stable equilibrium it may execute SHM.**

**This statement shows that equilibrium plays an important role in SHM and that’s why we are doing this review.**

__Meaning of Equilibrium :__

__Meaning of Equilibrium :__**For a particle or body,**

**If ΣF ^{→} = 0 it is said to be in translational equilibrium.**

**If Στ ^{→} = 0 it is said to be in rotational equilibrium.**

**If ΣF ^{→} is zero for a particle then Στ^{→} is also zero (or Στ^{→} is zero then ΣF^{→} is also zero). Therefore for a particle to be in equilibrium either we have to show ΣF^{→} = 0 or Στ^{→} = 0**

**A rigid body is said to be in equilibrium only when it simultaneously confirms translational as well as rotational equilibrium. So, for showing a rigid body in equilibrium we have to show ΣF ^{→} = 0 as well as Στ^{→} = 0**

__Stable , Unstable & Neutral Equilibrium__

__Stable , Unstable & Neutral Equilibrium__**Stable , Unstable and Neutral Equilibrium**

**Equilibrium can be further classified as stable, unstable and neutral equilibrium.**

**On being slightly disturbed from its equilibrium position, if a body**

**(i) tends to acquire the original configuration then the body is said to be in stable equilibrium.**

**(ii) tends to acquire a new position then the body is said to be in unstable equilibrium**

**(iii) remains at that position then the body is said to be in neutral equilibrium.**

**Stable, Unstable and neutral equilibrium in terms of potential energy**

**If potential energy of a body does not change with any change in its configuration then it is said to be in neutral equilibrium.**

**If potential energy of a body changes with change in its configuration then the body will have maximum potential energy at unstable equilibrium and minimum potential energy at stable equilibrium.**

__Stable Equilibrium And Oscillation :__

__Stable Equilibrium And Oscillation :__**Oscillation is intimately related with stable equilibrium.**

**To illustrate it, let us consider a typical curve between the position (x) of the particle and its potential energy (U) for a one dimensional particle motion in a conservative field.**

**Tangents drawn at B, C, D and E are parallel to the x-axis. This means, at these points, slope (dU/dx) is zero.**

**Recalling F = − (dU/dx) , we can further say that at B , C , D and E , force acting on the particle is zero i.e. these are equilibrium positions.**

**For portions BC and DE, an increase in the value of x corresponds to an increase in the value of U.**

**The slope of the curve at any point in this portion is positive and hence , force( F = − dU/dx ) is negative.**

**It means, in BC and DE region, the force acting on the particle tends to pull it in a region of lower potential energy.**

**Similarly it can be shown that for the portions AB and CD (where slope is negative and hence force is positive) again the force pulls the particle in the region of lower potential energy.**

**Thus any slight displacement of the particle, either way from the position of minimum potential energy results into a force tending to bring the particle back to its original position.**

**This force is often referred to as restoring force and site of minimum potential energy, as recalled earlier, is the position of stable equilibrium.**