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Roxas ross

**1.**Two identical charged particles which are point masses are fastened to the two ends of a spring of spring constant 100 N/m and the natural length 10cm.The system rests on a smooth horizontal table.The charge of each particle is 2*10^(-8)C.the extension of spring if the extension is small as compared to the natural length.

**2.**Coulomb's force =1/4πe* q^2/d^2

Sring energy= 0.5* k *x^2

Spring force=k*x

**3.**I used energy conservation theorem and since the final and initial velocities of the particles are 0 I obtained the extension which was twice the extension as compared to the answer i got by equating forces.the force method is given as the correct answer.what is wrong in my method?

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