Pure Si at 500 K has equal number of electron (n_e ) and hole (n_h ) concentration of 1.5 × 10^16 m^(-3). Doping by indium increases n_h to 4.5 × 10^22 m^(-3). The doped semiconductor is of

Q: Pure Si at 500 K has equal number of electron (ne ) and hole (nh ) concentration of 1.5 × 1016 m-3. Doping by indium increases nh to 4.5 × 1022 m-3. The doped semiconductor is of

(a) n-type with electron concentration ne = 2.5 × 1023 m-3

(b) p-type having electron concentration ne = 5 × 109 m-3

(c) n-type with electron concentration ne = 5 × 1022 m-3

(d) p-type with electron concentration ne = 2.5 × 1010 m-3

Ans: (b)

Sol: ni2 = ne nh

(1.5 × 1016 )2 = n_e (4.5 × 1022 )

ne = 0.5 × 1010 =5 × 109

nh = 4.5 × 1022

nh > ne (p-type)