Q: R is the radius of the earth and ω is its angular velocity and gp is the value of g at the poles. The effective value of g at the latitude λ = 60° will be equal to
(a) $g_p – \frac{1}{4}R \omega^2 $
(b) $g_p – \frac{3}{4}R \omega^2 $
(c) $g_p – R \omega^2 $
(d) $g_p + \frac{1}{4}R \omega^2 $
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Ans: (a)