# The angle of the dip at a place is 40.6° and the vertical component of the earths magnetic field BV = 6 ×10^-5 T. The total intensity….

Q. The angle of the dip at a place is 40.6° and the vertical component of the earths magnetic field BV = 6 × 10-5  T. The total intensity of the earth’s magnetic field at this place is (sin 40.6° = 0.65)

(a) 7 × 10-5 T

(b) 6 × 10-5 T

(c) 5 × 10-5 T

(d) 9.2 × 10-5 T

Ans: (d)

Sol: $\displaystyle B_v = B sin\theta$

$\displaystyle B = \frac{B_v}{sin\theta}$

$\displaystyle B = \frac{6\times 10^{-5}}{sin 40.6}$

$\displaystyle B = \frac{6\times 10^{-5}}{0.65}$

= 9.2 × 10-5 T