The angular displacement (in radian) of an accelerated flywheel is given by θ = 9t^3/32….

Q: The angular displacement (in radian) of an accelerated flywheel is given by $\theta = \frac{9 t^3}{32}$ . The linear velocity and acceleration of a point at a distance of 0.75 m from the axis of rotation at the instant, when magnitudes of its tangential acceleration and normal acceleration are equal respectively, are

(a) 7/8 m/s , (1/2) √6 ms-2

(b) 5/8 ms-1 , (2/5) √6 ms-2

(c) 9/8 ms-1 , (3/4) √6 ms-2

(d) 11/8 ms-1 , (2/3) √6 ms-2

Ans: (c)