# The angular momentum of a particle of mass 0.01 kg, position vector r = (10i + 6j ) metre and moving with a velocity 3 j  m/s about the origin will be

Q: The angular momentum of a particle of mass 0.01 kg, position vector $\vec{r} = (10 \hat{i} + 6 \hat{j} )$ metre and moving with a velocity $3 \hat{j}$ m/s about the origin will be

(a) $0.03 \hat{k}$ j-s

(b) $\frac{1}{3} \hat{k}$ j-s

(c) $3 \hat{k}$ j-s

(d) $0.3 \hat{k}$ j-s

Ans: (d)