Q: The angular momentum of a particle of mass 0.01 kg, position vector $ \vec{r} = (10 \hat{i} + 6 \hat{j} ) $ metre and moving with a velocity $3 \hat{j} $ m/s about the origin will be
(a) $ 0.03 \hat{k} $ j-s
(b) $ \frac{1}{3} \hat{k} $ j-s
(c) $ 3 \hat{k} $ j-s
(d) $ 0.3 \hat{k} $ j-s
Ans: (d)