The angular momentum of a particle of mass 0.01 kg, position vector r = (10i + 6j ) metre and moving with a velocity 3 j  m/s about the origin will be

Q: The angular momentum of a particle of mass 0.01 kg, position vector $ \vec{r}  = (10 \hat{i} + 6 \hat{j}  ) $ metre and moving with a velocity $3 \hat{j} $ m/s about the origin will be

(a) $ 0.03 \hat{k} $ j-s

(b) $ \frac{1}{3} \hat{k} $ j-s

(c) $ 3 \hat{k} $ j-s

(d) $ 0.3 \hat{k} $ j-s

Ans: (d)