Q: The binding energies per nucleon for a deuteron and α-particle are x1 and x2 respectively. What will be the energy Q released in the reaction 1H2 + 1H2 → 2He4 + Q
(a) 4 (x1 + x2 )
(b) 4(x2 – x1 )
(c) 2 (x1 + x2 )
(d) 2(x2 – x1 )
Ans : (b)
Sob: 1H2 + 1H2 → 2He4 + Q
Q – value = 4x2 – 4x1 = 4(x2 – x1 )