Q: The binding energies per nucleon for deuterium and helium are 1.1 MeV. And 7.0 MeV respectively.
what energy in joules will be liberated when 2 deuterons take part in the reaction.
Sol: 1H2 + 1H2 → 2He4 + Q
Binding energy per nucleon of helium (2He4) = 7 MeV
Binding energy = 4 × 7 = 28 MeV
Binding energy nucleon of deuterium (1H2) = 1.1 MeV.
Binding energy = 2 × 1.1 = 2.2 MeV.
Energy liberated (Q) = [28 – (2.2)2] = 23.6 MeV.
i.e Q = 23.6 × 106 × 1.6 × 10-19 J ;
Q= 37.76 × 10-13 J.