# The bond order in O2+ is the same as in

Q: The bond order in O2+ is the same as in

(A) N2+

(B) CN

(C) CO

(D) NO+

Sol:  Bond order of O2+  $\large = \frac{1}{2} (6-1) = \frac{5}{2}$

Bond order of N2+ $\large = \frac{1}{2} (5-0) = \frac{5}{2}$

Hence (A) is the correct answer.