Q: The centre of the ellipse 3x2 + 4y2 – 12x – 8y + 4 = 0 is
(A) (1, 1)
(B) (2, 1)
(C) (3, 1)
(D) none of these
Sol. The equation of the ellipse can be written as
3 (x2 – 4x + 4) + 4 (y2 – 2y + 1) = 12
⇒ $\large \frac{(x-2)^2}{4} + \frac{(y-1)^2}{3} = 1 $
⇒ (2, 1) is the centre.