Problem: The common chord of $ x^2 + y^2-4x-4y = 0 $ and $ x^2 + y^2 = 16 $ subtends at the origin an angle equal to
Sol. The equation of the common chord of the circles $ x^2 + y^2-4x-4y = 0 $ and $ x^2 + y^2 = 16 $ is
x + y = 4 which meets the circle x2 + y2 = 16 at points A(4,0) and B(0,4).
Obviously OA ⊥ OB.
Hence the common chord AB makes a right angle at the centre of the circle
x2 + y2 = 16
Hence (D) is the correct answer.