The energy of electron in first excited state of H-atom is – 3.4 eV its kinetic energy is

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Q: The energy of electron in first excited state of H-atom is – 3.4 eV its kinetic energy is

(a) -3.4 eV

(b) + 3.4 eV

(c) – 6.8 eV

(d) 6.8 eV

Ans: (b)

Sol: Kinetic energy = – Total energy

= -(-3.4 eV) = + 3.4 eV

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