Q: The equivalent capacitance between x and y is

(a) 5/6 μF

(b) 7/6 μF

(c) 8/3 μF

(d) 1 μF

Ans: (c)

Sol: Since 1 μF & 1 μF both are connected to terminal X are in parallel , C’ = 2 μF

Now C’ & remaining 1 μF are in series , $\large C” = \frac{2 \times 1}{2+1} = \frac{2}{3} \mu F$

Now C” & 2 μF are in parallel .

$C_{XY} = C” + 2 = \frac{2}{3} + 2 = \frac{8}{3} \mu F$