# The escape velocity of a particle of mass m varies as

Q: The escape velocity of a particle of mass m varies as

(a) m2

(b) m

(c) m0

(d) m-1

$\frac{1}{2}m v^2 + (-\frac{G M m}{R} ) = 0$
$\frac{1}{2}m v^2 = \frac{G M m}{R}$
$v = \sqrt{\frac{2 G M}{R}}$