The length of the wire OE is divided into five equal parts OA, AB, BC, CD and DE. The wire is made to hang from E and its length is…..

Q: The length of the wire OE is divided into five equal parts OA, AB, BC, CD and DE. The wire is made to hang from E and its length is , $ \displaystyle \frac{5 \sigma_b }{4 \rho g}$ where σb is the breaking stress and ρ is the density of the material of the wire. The point at which wire will break, is

Numerical

(a) A

(b) B

(c) C

(d) D

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Ans: (d)

Sol: Breaking Stress = Breaking force / Area = Weight/Area

σb = ALρg/A

L = σb/ρg

Length of wire = 5σb/4ρg

From O to D ,

Length = 4σb/4ρg = σ/ρg

Hence wire will break at point D

 

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