Q: The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If two neutrons and two protons combine to form a helium nucleus of mass 4.0015 amu, the B.E. of the helium nucleus will be
(a) 28.4 MeV
(b) 20.8 MeV
(c) 27.1 MeV
(d) 14.2 MeV
Sol: (a) 2 0 n1 + 2 1 p1 → 2 He4
Mass defect : Δm = (2 × 1.0087 + 2 × 1.0073 – 4.0015)
= 0.0305 amu
B. E. = 0.0305 × 931 = 28.4 Me V
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