Q: The moment of inertia of a rod about an axis through its centre and perpendicular to it is $\frac{1}{12} ML^2 $ (where M is the mass and L is the length of the rod). The rod is bent in the middle so that the two halves make an angle of 60°. The moment of inertia of the bent rod about the same axis would be
(a) $\frac{1}{48} M L^2 $
(b) $\frac{1}{12} M L^2 $
(c) $\frac{1}{24} M L^2 $
(d) $\frac{M L^2}{8 \sqrt{3}}$
Ans: (b)