Q: The moment of inertia of a then circular disc about an axis passing through its centre and perpendicular to its plane is I. Then, the moment of inertia of the disc about an axis parallel to its diameter and touching the edge of the rim is

Sol: $\large I = \frac{MR^2}{2}$

⇒ M R^{2} = 2I

M.I. of the disc about tangent in a plane

$\large = \frac{5}{4}MR^2 = \frac{5}{2} I $