The percent loss in weight after heating a pure sample of KClO3 (molecular weight = 122.5) will be

Q: The percent loss in weight after heating a pure sample of KClO3 (molecular weight = 122.5) will be

(A) 12.25

(B) 24.50

(C) 39.18

(D) 49.0

Sol : 2KClO3 → 2KCl + 3O2­

245 gm of KClO3 on heating shows a weight loss of 96 gm (of O2)

∴ 100 gm of KClO3 on heating shows a weight loss  $\large = \frac{96}{245} \times 100$

= 39.18%

Ans: (C)