# The potential energy of a 1 kg particle free to move along the x-axis is given by V(x) = (x^4/4 – x^2/2) J. The total mechanical energy of the particle 2 J . Then, the maximum speed (in m/s) is

Q: The potential energy of a 1 kg particle free to move along the x-axis is given by $V(x) = \frac{x^4}{4} – \frac{x^2}{2}$ J. The total mechanical energy of the particle 2 J . Then, the maximum speed (in m/s) is

(a) 2

(b) 3/√2

(c)√2

(d) 1/√2

Ans: (b)