Q: The potential energy of a 1 kg particle free to move along the x-axis is given by $ V(x) = \frac{x^4}{4} – \frac{x^2}{2} $ J. The total mechanical energy of the particle 2 J . Then, the maximum speed (in m/s) is
(a) 2
(b) 3/√2
(c)√2
(d) 1/√2
Ans: (b)