The potential energy of a 1 kg particle free to move along the X – axis is given by v(x) = (x^4/4- x^2/2) J. ..

Q: The potential energy of a 1 kg particle free to move along the X – axis is given by $ V(x) = \frac{x^4}{4}- \frac{x^2}{2} $ J. The total mechanical energy of the particle is 2 J. Then, the maximum speed (in ms-1) is

(a) 3/√2

(b) √2

(c) 1/√2

(d) 2

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Ans: (a)