# The potential energy of a 1 kg particle free to move along the X – axis is given by v(x) = (x^4/4- x^2/2) J. ..

Q: The potential energy of a 1 kg particle free to move along the X – axis is given by $V(x) = \frac{x^4}{4}- \frac{x^2}{2}$ J. The total mechanical energy of the particle is 2 J. Then, the maximum speed (in ms-1) is

(a) 3/√2

(b) √2

(c) 1/√2

(d) 2