Q: The radius of the oxygen nucleus 8O16 is 2.8 × 10-15 m. find the radius of lead nucleus 82Pb205.
Sol: $\large R_o \propto A^{1/3} $
$\large \frac{R_o}{R_{Pb}} = (\frac{A_o}{A_{Pb}} )^{1/3} $
$\large \frac{2.8 \times 10^{-15}}{R_{Pb}} = (\frac{16}{205} )^{1/3} $
Rpb = 6.55 × 10-15 m