# The resistance of galvanometer is 999 Ω. A shunt of 1 Ω is connected to it. If the main current is 10^(-2) A…

Q: The resistance of galvanometer is 999 Ω. A shunt of 1 Ω is connected to it. If the main current is 10-2 A, what is the current flowing through the galvanometer.

Sol: G = 999 Ω , S = 1 Ω ,  i = 10-2 A ; ig = ?

$\large i_g = \frac{S}{G+S}i$

$\large i_g = \frac{1}{99+1} \times 10^{-2}$

= 10-5 A