Q: The shortest distance between the two straight lines $\frac{x-4/3}{2} = \frac{y + 6/5}{3} = \frac{z-3/2}{4} $ and $\frac{5y+6}{8} = \frac{2z-3}{9} = \frac{3x-4}{5} $ is
(A) $\sqrt{29}$
(B) 3
(C) 0
(D) $6 \sqrt{10}$
Sol. Since these two lines are intersecting so shortest distance between the lines will be 0.
Hence (C) is the correct answer.