Q: The shortest distance between the two straight lines $\frac{x-4/3}{2} = \frac{y + 6/5}{3} = \frac{z-3/2}{4} $ and $\frac{5y+6}{8} = \frac{2z-3}{9} = \frac{3x-4}{5} $ is

(A) $\sqrt{29}$

(B) 3

(C) 0

(D) $6 \sqrt{10}$

Sol. Since these two lines are intersecting so shortest distance between the lines will be 0.

Hence (C) is the correct answer.