# The temperature coefficient of resistance of platinum is  α = 3.92 × 10^(-3) K^(-1) at 0 °C. Find the temperature at which

Q: The temperature coefficient of resistance of platinum is  α = 3.92 × 10-3 K-1 at 0 °C. Find the temperature at which the increase in the resistance of platinum wire is 10 % of its value at 0 °C.

Sol: $\large R_2 = R_1 + R_1 \times \frac{10}{100} = \frac{110 R_1}{100}= 1.1 R_1$

$\large \Delta t = \frac{R_2 – R_1}{R_1 \alpha }$

$\large \Delta t = \frac{1.1 R_1 – R_1}{R_1 \alpha } = \frac{0.1}{\alpha}$

$\large \Delta t = \frac{0.1}{3.92 \times 10^{-3}}$

Δt = 25.51 °C ; t2 = 25.51 + 20 = 45.51 °C.