Q: The two waves are represented by :
y1 = 10-6 sin(100t + x/50 + 0.5) m
and y2 = 10-2 cos(100t + x/50) m
where x is in metres and t in seconds. The phase difference between the waves is approximately:
(a) 1.07 rad
(b) 2.07 rad
(c) 0.5 rad
(d) 1.5 rad
Ans: (a)
Solution : y1 = 10-6 sin(100t + x/50 + 0.5)m
and y2 = 10-2 sin(100t + x/50 + π/2)m
y2 = 10-2 sin(100t + x/50 + 1.57 )m
Phase difference = (100 t + x/50 + 1.57 ) – (100 t + x/50 + 0.5 )
= 1.07 rad
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