The two waves are represented by : y1 = 10-6 sin(100t+x/50+0.5)m and y2 = 10-2 cos(100t+x/50)m

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Q: The two waves are represented by :

y1 = 10-6 sin(100t + x/50 + 0.5) m

and y2 = 10-2 cos(100t + x/50) m

where x is in metres and t in seconds. The phase difference between the waves is approximately:

(a) 1.07 rad

(b) 2.07 rad

(c) 0.5 rad

(d) 1.5 rad

Ans: (a)

Solution : y1 = 10-6 sin(100t + x/50 + 0.5)m

and y2 = 10-2 sin(100t + x/50 + π/2)m

y2 = 10-2 sin(100t + x/50 + 1.57 )m

Phase difference = (100 t + x/50 + 1.57 ) – (100 t + x/50 + 0.5 )

= 1.07 rad

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