The value of nC0 + n+1C1 + n+2C2 + ….+ n+kCk is equal to

Q: The value of nC0 + n+1C1 + n+2C2 + ….+ n+kCk is equal to

(A) n+k+1Ck

(B) n+k+1Cn+1

(C) n+kCn+1

(D) None of these

Sol. We have (1+x)n + (1+x)n+1 + ….+ (1+x)n+k

$\large = (1+x)^n \frac{(1+x)^{k+1}-1}{x} $

$\large = \frac{(1+x)^{n+k+1}-(1+x)^n}{x} $

Equating coefficients of xn

nCn + n+1Cn + ….+n+kCn = n+k+1Cn+1

nC0 + n+1C1 + n+2C2 + ….+ n+kCk

= n+k+1Ck = n+k+1Cn+1

Hence (A), (B) are the correct answer.