Q: The value of nC0 + n+1C1 + n+2C2 + ….+ n+kCk is equal to
(A) n+k+1Ck
(B) n+k+1Cn+1
(C) n+kCn+1
(D) None of these
Sol. We have (1+x)n + (1+x)n+1 + ….+ (1+x)n+k
$\large = (1+x)^n \frac{(1+x)^{k+1}-1}{x} $
$\large = \frac{(1+x)^{n+k+1}-(1+x)^n}{x} $
Equating coefficients of xn
nCn + n+1Cn + ….+n+kCn = n+k+1Cn+1
⇒ nC0 + n+1C1 + n+2C2 + ….+ n+kCk
= n+k+1Ck = n+k+1Cn+1
Hence (A), (B) are the correct answer.
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