# Two springs have force constants kA and kB = 2kA. The four ends of the springs are stretched by the same force…..

Q: Two springs have force constants kA and kB = 2kA. The four ends of the springs are stretched by the same force. Energy stored in spring A is E, then energy stored in spring B is

(a) E/2

(b) 2E

(c) E

(d) 4E

Ans: (a)

Sol: $\displaystyle U_A = \frac{1}{2}k_A x_A^2$

$\displaystyle U_A = \frac{k_A^2 x_A^2}{2 k_A} = \frac{F^2}{2k_A}$

Similarly , $\displaystyle U_B = \frac{F^2}{2k_B}$

$\displaystyle \frac{U_A}{U_B} = \frac{k_B}{k_A} = 2$

$\displaystyle \frac{E}{U_B} = 2$

$\displaystyle U_B = \frac{E}{2}$