# uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support. A block of mass 2 kg is attached…

Q:  A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support. A block of mass 2 kg is attached to the free end of the rope. A transverse pulse of wavelength 0.06 m is produced at the lower end of the rope. What is the wavelength of the pulse when it reaches the top of the rope?

Sol: $\large v = \sqrt{\frac{T}{\mu}}$

$\large \frac{v_T}{v_B} = \sqrt{\frac{T_T}{T_B}} = \sqrt{\frac{(6+2)g}{2g}} = 2$

$\large \lambda_T = 2 \lambda_B$

= 2 × 0.06 = 0.12 m