When a car of mass 1000kg is moving with a velocity of 20 m/s on a rough horizontal road, its engine is switched off…

Q: When a car of mass 1000kg is moving with a velocity of 20 m/s on a rough horizontal road, its engine is switched off. How far does the car move before it comes to rest if the coefficient of kinetic friction between the road and tyres of the car is 0.75 ?

Sol: Here v = 20 m/s, μk = 0.75, g = 10 ms2

Stopping distance $\large S = \frac{v^2}{2\mu_k g} $

S = 26.67m.